BD1063 dhydrochloride
目录号 : KM15077 CAS No. : 206996-13-6 纯度 : ≥98%

BD1063 dhydrochloride是有效选择性的sigma 1受体拮抗剂。

规格 价格 是否有货 数量
5mg
In-stock
10mg
In-stock
25mg
In-stock
50mg
In-stock
100mg 询价 In-stock
200mg 询价 In-stock
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生物活性

BD1063 dhydrochloride is a potent and selective sigma 1 receptor antagonist.

体内研究

BD1063 dose-dependently reduces ethanol self-administration in sP rats (3.3-11 mg/kg) and withdrawn, dependent Wistar rats (4-11 mg/kg) at doses that does not modify mean ethanol self-administration in non-dependent Wistar controls. BD1063 also reduces the breakpoints of sP rats to work for ethanol under a progressive-ratio reinforcement schedule. BD1063 dose-dependently reduces binge-like eating and the regularity of food responding, and blocks the increased eating rate in Palatable rats. In the light/dark conflict test, BD1063 antagonizes the increased time spent in the aversive compartment and the increased intake of the palatable diet, without affecting motor activity. The administration of BD1063 30 minutes before each paclitaxel dose prevents the development of cold and mechanical allodynia in WT mice. Moreover, the acute administration of BD1063 dose dependently reverses both types of paclitaxel-induced allodynia.

分子式
C13H18N2Cl2.2[HCl]
分子量
346.12
CAS号
206996-13-6
运输条件

Room temperature in continental US; may vary elsewhere.

储存方式
Powder -20°C 3 years
4°C 2 years
In solvent -80°C 6 months
-20°C 1 month
溶解性数据
In Vitro: 

H2O : 100 mg/mL (288.92 mM; Need ultrasonic)

配制储备液
浓度 溶剂体积 质量 1 mg 5 mg 10 mg
1 mM 2.8892 mL 14.4459 mL 28.8917 mL
5 mM 0.5778 mL 2.8892 mL 5.7783 mL
10 mM 0.2889 mL 1.4446 mL 2.8892 mL
*

请根据产品在不同溶剂中的溶解度选择合适的溶剂配制储备液;一旦配成溶液,请分装保存,避免反复冻融造成的产品失效。
储备液的保存方式和期限:-80°C, 6 months; -20°C, 1 month。-80°C 储存时,请在 6 个月内使用,-20°C 储存时,请在 1 个月内使用。

The molarity calculator equation
Mass (g) = Concentration (mol/L) × Volume (L) × Molecular Weight (g/mol)
The dilution calculator equation
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)
This equation is commonly abbreviated as: C1V1 = C2V2
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