PG01
目录号 : KM7069 CAS No. : 853138-65-5 纯度 : ≥98%

PG01 是一种有效的 CFTR Cl- 通道增效剂。PG01 对 E193K,G970R 和 G551D (CFTR突变体) 有效,Kd 值分别为 0.22 μM,0.45 μM 和 1.94 μM。PG01对 ΔF508(Ka 为 0.3 μM)也有效。PG01 在添加 Forskolin 后增加 ΔF508-CFTR Cl- 电流。

规格 价格 是否有货 数量
1mg
In-stock
5mg
In-stock
10mg
In-stock
50mg 询价 In-stock
100mg 询价 In-stock

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生物活性

PG01 is a potent CFTR Cl channel potentiator. PG01 can correct gating defects of CFTR mutants, is effective on b>E193K, G970R and G551D (CFTR mutants) with Kd values of 0.22 μM, 0.45 μM and 1.94 μM, respectively. PG01 is also effective on ΔF508 (Ka of 0.3 μM). PG01 increases ΔF508-CFTR Cl current after adding Forskolin.

体外研究

PG01 itself does not activate ∆F508-CFTR, produces substantial ∆F508-CFTR Cl current after the addition of 0.5 and 2 μM Forskolin. PG01 at 100 nM strongly stimulates channel activity with multiple channel openings observed. The apparent Kd for PG01 for G551D-CFTR activation is 1 μM, approximately 100-fold better than that of genistein. The potency for activation G1349D-CFTR by PG01 is even better at 40 nM. PG01 produces large currents in both G551D- and G1349D-CFTR expressing cells. The currents are sensitive to CFTRinh-172 and are not seen in nontransfected cells.

体内研究

Pharmacokinetic analysis of PG01 in rats is done by serial measurements of plasma concentrations after single bolus infusions (5 mg/kg). PG01 pharmacokinetics fitted a two-compartment model with half-times of <5 min and 130 min with volume of distribution 4 L. Microsome metabolism studies and rat pharmacokinetic analysis suggests significantly more rapid metabolism of PG01 than SF-03.

分子式
C28H29N3O2
分子量
439.55
CAS号
853138-65-5
运输条件

Room temperature in continental US; may vary elsewhere.

储存方式
Powder -20°C 3 years
In solvent -80°C 6 months
-20°C 1 month
The molarity calculator equation
Mass (g) = Concentration (mol/L) × Volume (L) × Molecular Weight (g/mol)
The dilution calculator equation
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)
This equation is commonly abbreviated as: C1V1 = C2V2
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